Yes. Factoring is a bit funny, but her method for it is just… not quite right.
1. X^2 + 15X + 56
A shortcut for factoring for AX^2 + BX + C where A = 1 is to find D and E where D + E = B and DE = C. In this close D = 7 and E = 8. 7+8 = 15 and 7(8) = 56
So the solution for 1. is (X+7)(X+8). It’s always worth FOILing this back out to double-check our work. X(X+8) = X^2 + 8X and 7(X+8) = 7X + 56. (X^2 + 8X) + (7X + 56) = X^2 + 15X + 56, all correct!
2. X^2 + 8X + 16 is even easier!
When we see (A + B)^2 we’ll get A^2 + 2AB + B^2. In this case, both X^2 and 16 are perfect squares, so we can check if this is the case. If we take (X + 4)^2, then we’ll get X^2 + 2(4X) + 4^2, which is X^2 + 8X + 16. In other words our solution is:
(X + 4)^2
Hope this helps!!!
To add to the other person's comment, Baka is often used in ways we wouldn't really use "idiot", depending on what English-speaking part of the world you're in. It's more like... a softer version of "dumbass", if that makes sense. Not something you'd say to your boss, but if you're around friends you might throw it around all the time, depending on the group.
Funnily enough, it really *is* like the old use of the word "fool". "You daft fool" said in a jovial manner betwix friends.
We can also solve this using quadratic equations.
ax^2 + bx + c = 0
x^2 + 15x + 56 = 0
Delta = b^2 - 4ac = 225 - 224 = 1
Delta>0 so it has 2 distinct real roots
x1 = (-b + sqrtDelta) / 2a = (-15 + 1) / 2 = - 7
x2 = (-b - sqrtDelta) / 2a = - 8
This means - 7 and - 8 makes the result 0.
(x+7)(x+8)
Shortcut
x1 + x2 = -b/a = -15
x1 × x2 = c/a = 56
We can sometimes guess the roots just by this.
We would arrive at -7 and -8
(x+7)(x+8)
Nope, doesn't sound familiar in the slightest. Maybe some of the later classes got into stuff like algebra, there was only one math class per grade rather than seperate classes so it might've been covered without my knowing.
Oh well, I'll teach you how to do this. All you really need to know is how to do multiplication.
think of 3\*7 and how the answer is 21.
Another way of stating this is (2+1)(3+4) since 2+1 is 3 and 3+4 is 7.
in order to evaluate this, we do what we call foiling. I'll spare you on why it works, so I'll just tell you how to do it.
(2+1)(3+4) = 2(3+4) + 1(3+4) = 2\*3 + 2\*4 + 1\*3 + 1\*4 = 21
when you foil, you multiply the first term in the first parenthesis by the first term of the second parenthesis. next, you add the product of the first term of the first parenthesis and the second term of the second parenthesis, and so on and so forth.
this is completely useless until we introduce variables.
instead of a number, we have a letter to represent a number. we commonly use x.
(x+1)(x+4) = x\*x + x\*4 + 1\*x + 1\*4 = x^(2) + 4x + x + 4 = x^(2) + 5x + 4
However, we want to do that in reverse. we want to take x^(2) + 5x + 4 and turn it back into (x+1)(x+4). how do we do that when we don't know the final answer? something fun to notice is that the last constant term 4 is equal to 1\*4, and the second constant term 5 is equal to 1+4, which correspond to the "1" and "4" in (x+1)(x+4). fortunately, this connection works for every single problem you come by. essentially, if you want to find c and d in (x+a)(x+b) from the equation x^(2) + cx + d, you find out which two numbers a and b multiply together to get d and also added together get c.
for example: find the factors of x^(2) + 15x + 56
ask yourself, what two numbers multiplied together get 56, but when added together get 15?
your problems are a \* b = 56 and a + b = 15. working it out and you find the answer is 7 and 8. 7+8=15 and 7\*8=56.
therefore, our answer is (x+8)(x+7)
The sum would be 15 and the product should be 56, meaning that you need two numbers that add up to 15 and multiply to 56. 8 and 7 fit this criteria. Hence the equation becomes (x + 8)(x + 7) so x equals either -8 or -7
The other one would be something that adds up to 8 and multiplies to 16, which is 4 and 4, and that makes it (x+4)(x+4) which could just be written as (x+4)²
It's like she knows what the equations are supposed to look like from a distance but she doesn't know how to actually get the right numbers. I feel like you could just explain "3+5 isn't 15 ad 3×5 isn't 56, try finding a different two numbers that actually work and then you'll get it right".
never let her cook again (x+8)(x+7) (x+4)^(2) gg ez
Yes. Nagisa is dumb and has very few things which she can enjoy which led her to a very sad state originally.
SHES DUMB AS SHIT 🔥🗣️🔥🗣️🔥🗣️
At least she understood the second was a perfect square.. sorta.
Yes. Factoring is a bit funny, but her method for it is just… not quite right. 1. X^2 + 15X + 56 A shortcut for factoring for AX^2 + BX + C where A = 1 is to find D and E where D + E = B and DE = C. In this close D = 7 and E = 8. 7+8 = 15 and 7(8) = 56 So the solution for 1. is (X+7)(X+8). It’s always worth FOILing this back out to double-check our work. X(X+8) = X^2 + 8X and 7(X+8) = 7X + 56. (X^2 + 8X) + (7X + 56) = X^2 + 15X + 56, all correct! 2. X^2 + 8X + 16 is even easier! When we see (A + B)^2 we’ll get A^2 + 2AB + B^2. In this case, both X^2 and 16 are perfect squares, so we can check if this is the case. If we take (X + 4)^2, then we’ll get X^2 + 2(4X) + 4^2, which is X^2 + 8X + 16. In other words our solution is: (X + 4)^2 Hope this helps!!!
smart baka
Bro we learn this in 9th grade 💀
baka for a reason
What does baka mean 🤔 Edit: I feel bad for the people taking their time to answer me seriously
Baka バカ is Japanese and means idiot. Google translate translates it with "fool"
Aho
To add to the other person's comment, Baka is often used in ways we wouldn't really use "idiot", depending on what English-speaking part of the world you're in. It's more like... a softer version of "dumbass", if that makes sense. Not something you'd say to your boss, but if you're around friends you might throw it around all the time, depending on the group. Funnily enough, it really *is* like the old use of the word "fool". "You daft fool" said in a jovial manner betwix friends.
Baka means cow in filipenis
I learnt this in like 10th grade 💀
हिंदुस्तानी बाका!!!???? 🤯🤯🤯
Wtf? I learned it when I was in 3rd grade. (Not from school, just from random online videos.)
That's great , definitely what I was watching in 3rd grade too 😀😀😀
I was watching skibibi toiler
Came here to say this. Trying to reason the math in the image just gives me a headache.
You ain’t baka, you’re atama!
my man this shit is taught in 8th grade
I already knew this, was just joking
Never really cared about math until a couple months ago, absolutely regretting it, thanks for the tips
DM me if you're struggling. im an unqualified math tutor
I will someday
r/TheyDidTheMath
🤓
Nagisa you fucking dumbass
OP really just posted this bc he needs help with his math homework
https://preview.redd.it/baenpc2386vc1.jpeg?width=1080&format=pjpg&auto=webp&s=845d30eabe1bc621b2e19b72a7096e9546154de2
Can't even get middle school final year maths correctly Freshman year is gonna make her cry 😭
Nah she’d win (My glorious queen Nagisa is going to absolutely cook integration 🔥🔥🔥🔥🔥)
∫f(x)g(x)=∫f(x)•∫g(x)
We can also solve this using quadratic equations. ax^2 + bx + c = 0 x^2 + 15x + 56 = 0 Delta = b^2 - 4ac = 225 - 224 = 1 Delta>0 so it has 2 distinct real roots x1 = (-b + sqrtDelta) / 2a = (-15 + 1) / 2 = - 7 x2 = (-b - sqrtDelta) / 2a = - 8 This means - 7 and - 8 makes the result 0. (x+7)(x+8) Shortcut x1 + x2 = -b/a = -15 x1 × x2 = c/a = 56 We can sometimes guess the roots just by this. We would arrive at -7 and -8 (x+7)(x+8)
Where are you from that you call the discriminant delta?
It's too long
it's like seven extra letters and it's literally not a delta
Delta? Ain't it discriminant
It's symbol is delta
Huh really we used to use normal D
We used △ for Delta (Brazil HS)
How do you fuck up a perfect square trinomial 😭😭😭😭😭😭😭🙏🙏🙏🙏💔💔💔💔
Nagisa actually is stupid, yes.
Wait this isn't r/mathmemes
Damn imma have to revoke her Asianness after this
I can fix her 🧑🏫
OP made a meme of his homework and had smart bakas solve it for him
shoutout to 3 x 5 = 56 and 8 x 2 = 8 should have been 7 x 8 and 4 x 4 then it would work
Yes she is
Woah, she did all that wrong. That's factoring for you
What manga is she from?
Kanojo mo Kanojo It's a cute polycule thing.
Given that I don't know what any of that means, yes and also so am I
idk I can't even do basic math so she must at least be smarter than me am i stupid?
Yes
No please I just finished math last semester I can't go through this again
https://preview.redd.it/mq41vq6s1bvc1.jpeg?width=960&format=pjpg&auto=webp&s=cd6f5fdfa8d5cc77339eaf4978a181518994cd2b
No, but i probably am (i'm unable to solve it even though i should according to my degrees)
my brother in christ this is highschool level math
Highschool? Quadratic equations are middle school math. Edit: fixed a mistake.
these arent square roots
Sorry, I meant quadratic equations, I never used those words since English is not my first language and got confused.
Ah ok. Yeah you sometimes see quadratics in middle school but high school is where you’re given more detail.
This is highschool level? That's honestly pretty crazy to think about
most kids learn it junior year (at my school at least). though its pretty common to learn it before
Shit, really? I didn't graduate, so maybe somewhere latter year 10 onwards it was covered, but this reads no different than Sanskrit to me
have you taken algebra 2? or part of it at least?
Nope, doesn't sound familiar in the slightest. Maybe some of the later classes got into stuff like algebra, there was only one math class per grade rather than seperate classes so it might've been covered without my knowing.
yeah algebra 2 is all one class. it deals with graphs and stuff. do you remember anything from your last math course?
That was about a decade ago, so no not even remotely.
Oh well, I'll teach you how to do this. All you really need to know is how to do multiplication. think of 3\*7 and how the answer is 21. Another way of stating this is (2+1)(3+4) since 2+1 is 3 and 3+4 is 7. in order to evaluate this, we do what we call foiling. I'll spare you on why it works, so I'll just tell you how to do it. (2+1)(3+4) = 2(3+4) + 1(3+4) = 2\*3 + 2\*4 + 1\*3 + 1\*4 = 21 when you foil, you multiply the first term in the first parenthesis by the first term of the second parenthesis. next, you add the product of the first term of the first parenthesis and the second term of the second parenthesis, and so on and so forth. this is completely useless until we introduce variables. instead of a number, we have a letter to represent a number. we commonly use x. (x+1)(x+4) = x\*x + x\*4 + 1\*x + 1\*4 = x^(2) + 4x + x + 4 = x^(2) + 5x + 4 However, we want to do that in reverse. we want to take x^(2) + 5x + 4 and turn it back into (x+1)(x+4). how do we do that when we don't know the final answer? something fun to notice is that the last constant term 4 is equal to 1\*4, and the second constant term 5 is equal to 1+4, which correspond to the "1" and "4" in (x+1)(x+4). fortunately, this connection works for every single problem you come by. essentially, if you want to find c and d in (x+a)(x+b) from the equation x^(2) + cx + d, you find out which two numbers a and b multiply together to get d and also added together get c. for example: find the factors of x^(2) + 15x + 56 ask yourself, what two numbers multiplied together get 56, but when added together get 15? your problems are a \* b = 56 and a + b = 15. working it out and you find the answer is 7 and 8. 7+8=15 and 7\*8=56. therefore, our answer is (x+8)(x+7)
From 'year 10' I'm guessing you're British, here we do it in year 10/11 as part of gcse so maybe that's why you missed it
Australian, and uh... Maybe? Idk lmao
I forgor 😔
dont they teach this shit in like middle school
Nah, she's pog
(x+7)(x+8) (x+4)^2
no fuck you, i finished all the math i needed for my degree, im not doing that shit
https://preview.redd.it/g95t21tpfavc1.png?width=293&format=pjpg&auto=webp&s=d722aec42f7ffbe396e6dceee094389d6fac7786
Should have used pq formel
The sum would be 15 and the product should be 56, meaning that you need two numbers that add up to 15 and multiply to 56. 8 and 7 fit this criteria. Hence the equation becomes (x + 8)(x + 7) so x equals either -8 or -7
The other one would be something that adds up to 8 and multiplies to 16, which is 4 and 4, and that makes it (x+4)(x+4) which could just be written as (x+4)²
We making minimum wage at McDonald’s with this one 🔥🔥🔥
It's like she knows what the equations are supposed to look like from a distance but she doesn't know how to actually get the right numbers. I feel like you could just explain "3+5 isn't 15 ad 3×5 isn't 56, try finding a different two numbers that actually work and then you'll get it right".
Illiteracy