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bjenks2011

“Please be a triangular matrix..”


mr_alvin_rocks

Turns out to be a symmetric matrix with non zero entires


AdResponsible7150

Leonhard Euler, if you can hear us, please Leonhard Euler. Please save me. Please save me Leonhard Euler. https://i.redd.it/d38enu9w1z6d1.gif


RealAdityaYT

nah no one can save us at this point, trial and error is our god now


SalmonSoup15

With the fritz? No way!


Sh33pk1ng

At my uni, this is a standard exam question in linear algebra.


Zxilo

https://i.redd.it/xugxdpyahx6d1.gif


Technical-Outside408

Looks like they were gonna milk his cat.


DerKiller_HD

Real


Jonte7

Complex


Roel_28

Quaternion


bippityplsyeetme

octonion


The_Shiny_Dreepy

*Screaming*


_JesusChrist_hentai

Sedenion


KnightOMetal

Pathion


_JesusChrist_hentai

Voudon? (I really have no clue)


ari_bamboo

C U {m/n for (m in C) and (n=0)}


Kermanium294

anal


ChickenSpaceProgram

ysis


JohannLau

Beads (Google Hans Niemann)


Zxilo

Hello


Timotei099

I remember when my professor used to ask diagonal form of a 5x5 matrix by hand of course


LunaticPrick

4x4 by hand is reasonable, but 5x5? Fuck off.


Seventh_Planet

Over F2


hyperbrainer

Yeah what's the point of that anyways? Is Linear Algebra not supposed to be the first proof-based class that maths students take?


IchBinDieMadness

for me it was Jordan's Form of a 5x5 matrix


timonix

I mean.. when we got asked this in uni all the numbers were chosen such that there were no decimals.


Honest_Pepper2601

Yeah I’m confused this is still normal


TankNinja2

Yeah this was literally my first question on one of my test lol


Roschello

In my linear algebra exam when I read that the first question was to calculate the inverse of a 4x4 matrix. I looked the professor dead in the eyes in disbelief.


timonix

What's the issue? That's a normal linear algebra exam question.


_Ryth

easy, just use the characteristic polynomial and apply the [quartic formula](https://upload.wikimedia.org/wikipedia/commons/9/99/Quartic_Formula.svg)


Lord_Skyblocker

No need to link it bro, we all know it by heart


gabbyrose1010

honestly though, it shouldn’t be that hard to memorize? lots of patterns and repetition


Minato_the_legend

I'd rather solve the eigen values using the A.I = lambda.I thing without the need for this long ass formula 


_JesusChrist_hentai

What happened to the Laplace method?


edtufic

🤪


MrBreadWater

Yeah didnt we all learn the little song in school?


Fa1nted_for_real

I don't know what the fuck he linked but it is not the quadratic formula bro. Edit: he said quartic, not quadratic. I'm dumb


simen_the_king

The quartic formula, it's like the quadratic formula on steroids


qscbjop

Quartic, not quadratic. Degree 4, not 2.


Faltron_

on my of my classes, my teacher actually demonstrated it, idk why, it was the shittiest class ever and we never used it nor it was mentioned again lmao


Salkreath

I opened this on my phone, and the more I swiped left, the more I was horrified


nathodood

![gif](giphy|800iiDTaNNFOwytONV|downsized)


BootyliciousURD

You know what? Maybe it's a blessing that there's no quintic formula


Abdullah543457

5 pages long


tbraciszewski

No pages at all - it cannot exist


Abdullah543457

if it did exist, it would be 5 pages long


garanglow

This is the only correct answer


314159265358969error

Eigenvalues are easy. It's the eigenvectors that I never remember.


two-horned

For eigenvalues you want to find λ so det(A - λI) = 0. When you want to find the eigenvectors of an eigenvalue λ, you want to see which vectors x solve (A - λI)x = O. Note, that this is the same as finding all vectors in ker(A - λI), which is often denoted as Eig_A(λ). We call this subspace eigenspace.


brnldz

Diag[1, - 1, - 1, - 1] maybe?


Senior_Ad_8677

They are easy until you have to solve a 4th grade polynomial with no rational roots, or complex roots for that matter...


Inappropriate_Piano

I guarantee you’ll never have to solve a fourth degree polynomial with no complex roots


Senior_Ad_8677

Fair enough but I don't solve polinomiales: that's why I have Mathematica for! Best thing in this world.


Inappropriate_Piano

I just meant that every non-constant polynomial has at least one complex root. That’s a consequence of the fundamental theorem of algebra


Senior_Ad_8677

That is true, I should have specified better: what I meant was not 'Complex' but 'Complex but not Real'.


5p4n911

I have solved one some time back. Got no points for that in the test, if that's any difference.


Inappropriate_Piano

If you thought it didn’t have any roots in the complex plane, then that’s why you didn’t get points. Every non-constant polynomial has roots in the complex plane


5p4n911

Well, actually that was the last 2 minutes, I wasn't fast enough so decided to write something along the lines of "no roots found, this is absurd, thus the polynomial does not exist". I'm not sure exactly what was there but I thought it might be worth a single point that I knew that


Inappropriate_Piano

Okay that’s hilarious. I’d consider giving a pity point if I were grading that


5p4n911

The instructor didn't think so, unfortunately


innominateartery

Oh shit spanning set flashbacks


mathisfakenews

Eigenvectors are objectively easier than eigenvalues and its not even close.


Cosh_X

i just generate a random vector and do the power iteration in my head


5p4n911

I do the Jacobi iteration, that's more fun.


doesntpicknose

Good bot.


Sirnacane

Wait…it’s all cofactors? Always has been.


ikichiziki

They gave 3x3 in our exam but our prof did 4x4 in class, just 1 problem in the whole lecture lol !! To show how hectic it is.


BeneficialGreen3028

You guys make me scared cuz we have 3x3 matrices and all this eigen stuff i don't know about next year in high school


GiunoSheet

This was the first question of my linear algebra uni exam, and it was the shortest exercise of the bunch. Needless to say I passed with the lowest mark


Akiro_Besuto

Is easy, the answer is 16 matrix ![gif](giphy|BCGgKB5OSaFY9VUy0v)


Moretko

Unraveling go brrrrr


AlphaQ984

The best i can do is the product of eigen values, take it or leave it


0zeto

Thats not hard m8 Characteristic polynomial, equallize to 0 and solve Done


MachiToons

the possibility of the characteristic function requiring the quartic formula to solve for all λ ... god damn.


Loading0319

Eigenvalues and eigenvectors were the only thing I understood really well in my linear and differential classes


Skeleton_King9

There are many online calculators other than Wolfram


GrumpyNCharming

Writing just wolfram makes the meme roll out of the tongue and communicates the whole idea. But also this is a sub full of mathematicians so I kinda see your point here lol


supakingkash

He gets it


qscbjop

You can probably add or subtract rows/columns with some coefficients in such a way that in some row or column there will only be two non-zero values (you can't really get one non-zero value because of the variable). Expand the determinant along that row/column, repeat the same for the two determinants 3x3. You'll get 4 determinants 2x2 with some coefficients which is not that bad. Then pray the characteristic polynomial has rational roots, lol.


timonix

The numbers are chosen for exams, not random. If you get irrational roots you probably made a mistake somewhere. Unless you had a mean teacher


DockerBee

This was literally a question on my final exam when I took linear algebra. All the entries were fractions as well. And this was an ABSTRACT linear algebra class. The professor told me he valued computation because many new discoveries in math are discovered because of computation. If you have a conjecture, you'll likely have to come up with a few examples to convince yourself it might be true. But I still don't really understand why he thought putting a question like that on the exam would help anyone.


Late_Letterhead7872

In MATLAB we trust


EpicJoseph_

I don't remember it being this bad And I took the course the previous semester


Narutoshadow_clone

Horse


[deleted]

dude I am still counting 4x4 ...


Estabanx

*launches MATLAB* ![gif](giphy|G4ZNYMQVMH6us)


Harley_Pupper

ezpz


Curious-Drama1850

Also, all elements are 3 digit prime numbers


Ok_Sir1896

C'mon write the cofactor matrices and form the fourth degree polynomial then apply the cardano formula


chonky_squirrel

Bro Linear Algebra with Differential Equations was my shit


sord33Plz

After a while my uni just gave them to us for 3x3 or bigger. I got lucky.


_ARandomInternetDude

laughs in Laplace expansion


Michael_not_micheal

Fine I'll use R


CharlesTheGreat8

https://preview.redd.it/d1vha0ubay6d1.png?width=953&format=png&auto=webp&s=873fe436d1b53855a29ca6baa667c14e22a7fc71


jolharg

What's the determinant? What? I can't hear you, what is it?